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OpenStudy (anonymous):
What are the amplitude, period, and midline of the function?
Amplitude: 6; period: 2π; midline: y = −3
Amplitude: 6; period: π; midline: y = −3
Amplitude: 3; period: π; midline: y = −2
Amplitude: 3; period: 2π; midline: y = −2
OpenStudy (anonymous):
what function
OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what are the min and max of this function?
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jimthompson5910 (jim_thompson5910):
Correct. You use them with these formulas
\[\Large \text{Amplitude} = \frac{\text{Max} - \text{Min}}{2}\]
\[\Large \text{Midline} = \frac{\text{Max} + \text{Min}}{2}\]
OpenStudy (anonymous):
amp=3 midline=-2
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
they both say that though
jimthompson5910 (jim_thompson5910):
start at a peak (say when x = 0)
then go to the next peak on the right
how far did you move along the x axis?
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OpenStudy (anonymous):
to pi
jimthompson5910 (jim_thompson5910):
that means the period is pi
jimthompson5910 (jim_thompson5910):
it repeats itself every pi units
OpenStudy (anonymous):
thank you it makes so much since!!! help with one more for tonight?
jimthompson5910 (jim_thompson5910):
sure
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OpenStudy (anonymous):
OpenStudy (anonymous):
i tried the desmos but it didnt work
jimthompson5910 (jim_thompson5910):
for each answer choice, you graph the left side and right side (you'll have 2 different functions for each choice)
OpenStudy (anonymous):
so put on side of the = in then hit enter and then the other side?
jimthompson5910 (jim_thompson5910):
yeah for choice A you'll type in
x^2-2x+3 for one box
and
2x^2-8x-3 for another box
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jimthompson5910 (jim_thompson5910):
and then see if things match up
jimthompson5910 (jim_thompson5910):
repeat for the other choices
but make sure you turn off the choices you cross off the list so you don't get tons of clutter
OpenStudy (anonymous):
i got d
jimthompson5910 (jim_thompson5910):
me too
OpenStudy (anonymous):
Yep same thing i did! thank you so much again!
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