Question

The midpoint of (8, 6) and (-2, 12) is (3, 9)?

Answer 1

True/False

Answer 2

Midpoint of \((x_1,y_1)\) and \((x_2,y_2)\) is \(\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)\)

Answer 3

Here, you are given points \((8,6)\) and \((-2,12)\)

Answer 4

\(x_1 = 8\\~\\x_2 = -2\\~\\y_1 = 6\\~\\y_2 = 12\)

So you have \(\left(\dfrac{8+\text-2}2,\dfrac{6+12}2\right)\quad\Longrightarrow\quad ?\)

Answer 5

its false

Answer 6

thank you

Answer 7

Explain why @slade

Answer 8

just look on a graph

Answer 9

I think you should take a second look at graph.