Ask your own question, for FREE!
Physics 14 Online
OpenStudy (asib1214):

Yelp!!!

rvc (rvc):

@Michele_Laino

rvc (rvc):

what is your ans?

OpenStudy (michele_laino):

since we have three complete cycles within 4.8 meters, then the wavelength is: 4.8/3=1.6 meters

rvc (rvc):

since we have 3 waves so divide 4.8 by 3 because one wave is equal to wavelength

rvc (rvc):

lol sorry i did not see your post @Michele_Laino

OpenStudy (michele_laino):

no worries :) @rvc

OpenStudy (michele_laino):

the requested velocity, is: 4.8/6=...meters/seconds

OpenStudy (michele_laino):

period is T= 6 /3 =...second frequency f= 1/T =... Hz

OpenStudy (michele_laino):

if the velocity of our wave is unchanged, then we can apply this formula: \[\Large \lambda f = v\] from which we get: \[\Large \lambda = \frac{v}{f} = \frac{{0.8}}{2} = ...meters\]

OpenStudy (asib1214):

this is how i did it, i first took the inverse of the Ferquency.....F=1/T which agve me the period

OpenStudy (michele_laino):

how did you get 14.5 meters/second

OpenStudy (michele_laino):

v=traveled space/time interval= 4.8/6=0.8 m/second

OpenStudy (michele_laino):

period is T=6/3= 2 seconds

OpenStudy (michele_laino):

I think taht: since within 6 seconds we have three complete waves, then the period is:T=6/3= 2 seconds

OpenStudy (michele_laino):

so the corresponding frequency is: f=1/T= 1/2=0.5 Hertz

OpenStudy (asib1214):

when solving for the very first question wavelength.

OpenStudy (asib1214):

i mean second cuz time is given after the wavelength question :(

OpenStudy (asib1214):

so do we assume we don't know the time while solving for wavelength

OpenStudy (michele_laino):

as I wrote before, in the last part of the first question, we have to assume that the speed of our wave is the same as before, namely, it is 0.8 m/second

OpenStudy (asib1214):

@rvc do i figure out the amplitude? Please help!!!

OpenStudy (asib1214):

@Astrophysics

OpenStudy (asib1214):

how do i figure out the amplitude? Please help!!!

OpenStudy (asib1214):

the picture is at the top.

OpenStudy (astrophysics):

|dw:1435727528455:dw| you can find the amplitude using \[Amplitude = \frac{ Distance }{ Frequency }\]

OpenStudy (astrophysics):

They are related.

OpenStudy (astrophysics):

No, the amplitude here is measured in decibels here. I think you're just confusing it because of the formula/ units but not really sure about what this actually means.

OpenStudy (astrophysics):

\[\lambda = \frac{ v }{ f }\]

OpenStudy (asib1214):

can you quickly guide me what to do Please?!?!?!?!

OpenStudy (astrophysics):

Slow down, ok so we have |dw:1435728513829:dw| so we have 3 complete cycles here, so our wavelength is 4.8/3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!