Yelp!!!
@Michele_Laino
what is your ans?
since we have three complete cycles within 4.8 meters, then the wavelength is: 4.8/3=1.6 meters
since we have 3 waves so divide 4.8 by 3 because one wave is equal to wavelength
lol sorry i did not see your post @Michele_Laino
no worries :) @rvc
the requested velocity, is: 4.8/6=...meters/seconds
period is T= 6 /3 =...second frequency f= 1/T =... Hz
if the velocity of our wave is unchanged, then we can apply this formula: \[\Large \lambda f = v\] from which we get: \[\Large \lambda = \frac{v}{f} = \frac{{0.8}}{2} = ...meters\]
this is how i did it, i first took the inverse of the Ferquency.....F=1/T which agve me the period
how did you get 14.5 meters/second
v=traveled space/time interval= 4.8/6=0.8 m/second
period is T=6/3= 2 seconds
I think taht: since within 6 seconds we have three complete waves, then the period is:T=6/3= 2 seconds
so the corresponding frequency is: f=1/T= 1/2=0.5 Hertz
when solving for the very first question wavelength.
i mean second cuz time is given after the wavelength question :(
so do we assume we don't know the time while solving for wavelength
as I wrote before, in the last part of the first question, we have to assume that the speed of our wave is the same as before, namely, it is 0.8 m/second
@rvc do i figure out the amplitude? Please help!!!
@Astrophysics
how do i figure out the amplitude? Please help!!!
the picture is at the top.
|dw:1435727528455:dw| you can find the amplitude using \[Amplitude = \frac{ Distance }{ Frequency }\]
They are related.
No, the amplitude here is measured in decibels here. I think you're just confusing it because of the formula/ units but not really sure about what this actually means.
\[\lambda = \frac{ v }{ f }\]
can you quickly guide me what to do Please?!?!?!?!
Slow down, ok so we have |dw:1435728513829:dw| so we have 3 complete cycles here, so our wavelength is 4.8/3
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