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Convert the Cartesian equation x^4 - y^4 = 16 to a polar equation? r^2 = 16/cos2θ r^4 = 16/cos2θ r^2 = 8
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so far i have r^4(cos^4(theta)-sin^4(theta))=16
Do you know any trig identities to simplify that?
I think the answer is B, but i'm not totally sure
I don't know I just learned this today and my worksheet doesn't say anything about it.
But I think your right.
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Thank you
I think it simplifies to cos(2x)(1)
r^4cos(2x)=16 r^4=16/cos(2x)
Ok thanks!
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that explains the identity
no problem
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