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Find an equation for the nth term of the arithmetic sequence. -17, -12, -7, -2, ... an = -17 + 5(n + 2) an = -17 + 5(n + 1) an = -17 + 5(n - 1) an = -17 x 5(n - 1)
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\[a_n=a_1+d(n-1)\] a_1 = first term d = common difference (2nd # - 1st #)
what's your a_1 and d?
a1 would be -17 and d would be 5
would it be -17 + 5n-5?
or do i not distribute the 5, nvm i got it, Thank you!
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-17+5(n-1)
right, don't distribute
can i ask you one more tho? @peachpi on another post tho
ok
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