Let f(x) = -2x - 7 and g(x) = -4x + 3. Find (f o g)(-5)
(f o g)(-5) is the same as f(g(-5)) the first task is to find g(-5). Do you know how to do this?
A. -53 C.23 D.3
No i have no clue
@satellite73
Could you help @jim_thompson5910
@SolomonZelman
g(x) = -4x + 3 g(-5) = -4(-5) + 3 ... replace every x with -5 g(-5) = ??
On OS we help people learn; Jim is trying to make sure you are understanding this
Oh i know and i defiantly want the help
(f o g)(-5) well first let's do (f o g ) which means that the g(x) equation is placed inside the f(x) equation
20+3
whoa... let's do this step by step
Oh sorry i was replying to what @jim_thompson5910 started
so you should find that g(-5) = 23 agreed?
correct
f(g(-5)) becomes f(23) after you replace g(-5) with 23
now follow the same basic steps to calculate f(23)
ok it's ok didn't see that :) anyway given the functions f(x) = -2x-7 and g(x) = -4x+3 we need to place g(x) =-4x+3 into the f(x) so for every x in f(x) the g(x) takes it's place
so the end result should be -2(insert g(x) function here)-7
then combine like terms and evaluate when x = -5
im lost
Is the answer 23?
no
I agree with jim there's more to be done...
ok im ready to learn the rest
k.. so did you already place your g(x) into your entire f(x) function?
No i got lost after we got f(23)
To calculate f(23), replace every x in f(x) with 23 f(x) = -2x - 7 f(23) = -2*23 - 7 f(23) = ??
that means x = 23 evaluate the f(x) function
it's just like the g(x) one
-46
f(23)=-46-7
keep going
almost there
46-7=39
we have two negative numbers so the negative numbers are supposed to increase, not decrease
opps wrong
-53
yes!
good
do you want to see another method of solving this equation as a reference?
yay we did it
yes that would be great
ok so here's how I would tackle this problem (f o g ) (-5) first I will tackle f o g portion and then evaluate when x = -5 so f o g means that we place our g(x) function inside all x's of the f(x) function f(x) = -2x-7 and g(x) = -4x+3 f o g -2(-4x+3)-7 distribute the -2 8x-6-7 8x-13 so our f o g = 8x-13 now evaluating when x = -5 f o g (-5) = 8(-5)-13 = -40-13 = -53
Can you guys help me solve another @UsukiDoll @jim_thompson5910
sure
Let f(x) = x + 2 and g(x) = x2 Find ( g o f)(-5)
\[\large f(x) = x+2, g(x) = x^2 \]
this is similar to the previous problem. while our x still remains the same g o f means that we place our entire f(x) function inside the x's of the g(x) function so g o f = (insert f(x) here)^2
so is x -2?
our f(x) = x+2 and we need place it inside g(x). Since g(x) =x^2 g o f = (f(x) function)^2
so X^2+X+2?
\[g o f =(x+2)^2 \] that second power means write (x+2) two times after that, we need to use FOIL to expand
your gonna have to hold my hand on this one cuz im totally lost lol im sorry
alirght.. so we write (x+2) two times (x+2)^2 means (x+2)(x+2) now using FOIL (x)(x)+2(x)+2(x)+(2)(2) so what's 2 x 2 2x + 2x and x times x I guess that's the closest way of notating multiplication
Ok so where do we go from this?
first tell me what 2 x 2 is then tell me what 2x+2x is .. I will factor out the x to make it easier x(2+2)
2x2=4
2x+2x=4X
mhm last one what is (x)(x) . I'll make this easier by rewriting it and using the addition exponential rule, \[\large (x)(x) \rightarrow x^1x^1 \rightarrow x^{1+1}\] so you just have to solve for the exponent part. what is 1+ 1
2
\[x ^{2}\]
yes so now we have \[g o f =x^2+4x+4 \]
so now we evaluate this when x = -5. so replace all x's with -5
25-20+4=9
\[g o f (-5) =(-5)^2+4(-5)+4\] \[g o f (-5) =25-20+4 \rightarrow 5+4 = 9 \] correct
Thank you very much
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