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Mathematics 15 Online
OpenStudy (anonymous):

Is this right or wrong? 11. Solve the inequality. Show your work. |r + 3| ≥ 7 | r + 3|≥ 7 -3 -3 | r | ≥ 4 If I plug the the 4 into r's place |4+3| ≥7

OpenStudy (loser66):

for absolute value problem, you need do: \(| r+3|\geq 7\) \(-7\geq r+3\geq 7\) \(\bullet \) first and middle : \(-7 \geq r+3 \) -3 both sides \(-11\geq r\), that means \(r\leq -11\) (namely *) \(\bullet\) middle and last: \(r+3\geq 7\) -3 both sides, \(r\geq 4\) (namely **) Combine * and **, you have either \(r\leq -11\) or \(r\geq 4\) is the solution for the expression.

OpenStudy (loser66):

|dw:1435930768684:dw|

OpenStudy (loser66):

|dw:1435930801109:dw|

OpenStudy (loser66):

|dw:1435930869866:dw|

OpenStudy (loser66):

Hence, your answer should be both with OR between them. I meant \(r\leq -11\) OR \(r\geq 4\)

OpenStudy (anonymous):

So i have to move my 7 over to the left?

OpenStudy (anonymous):

Okay.

OpenStudy (loser66):

Actually, you NOT move 7, just put -7 to the left.

OpenStudy (anonymous):

Do the original 7 stay on or do i subtract it?

OpenStudy (loser66):

stay!! just put an extra value by opposite of 7 to the left.

OpenStudy (loser66):

In general, if |a| < 7, to solve it, you put one more value on the left by opposite value of number , like -7<a<7

OpenStudy (anonymous):

Okay. Do i include it when i'm subtarcting 3?

OpenStudy (loser66):

if |a|> 7, again, put one more value on the left -7 >a >7 On that way, you take off the absolute sign and solve part by part like above.

OpenStudy (loser66):

After taking off the absolute value sign, you solve as usual, no absolute value any more.

OpenStudy (anonymous):

Alright. So i won't need the bars anymore?

OpenStudy (loser66):

yup

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