Solve the system by elimination.

-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

i just need to know how to do it i honestly can do it by my self need help!!!!

Question

Solve the system by elimination.

-2x+2y+3z=0
-2x-y+z=-3
 2x+3y+3z=5

i just need to know how to do it i honestly can do it by my self need help!!!!

dayianaforever · Answer

please anyone

rishavraj · Answer

see add up eqation 1 and 3 .....x gets eliminated....
and subtract equation 2 from 1 ... x gets eliminated ...

rishavraj · Answer

http://prntscr.com/7om5on

anonymous · Answer

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.
 
So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.

rishavraj · Answer

or else multiply equation 2 from -1 and then add it with equation 1....x gets eliminated

dayianaforever · Answer

ohh okay thank you @rishavraj and @NoahDabreo