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Mathematics 13 Online
OpenStudy (anonymous):

Another integral problem!

OpenStudy (anonymous):

OpenStudy (anonymous):

So I know that the integral is -cos^3 (x) / 3 + c for the integral of cos^2 (x) * sin(x)

OpenStudy (anonymous):

So the first part would be zero because 2/3 - 2/3 is 0

OpenStudy (anonymous):

I mean 1/3 - 1/3

OpenStudy (anonymous):

But what about the second part? Wouldn't that just be adding 1/3 and 1/3 together to get 2/3?

ganeshie8 (ganeshie8):

For the second part, you need to honor the absolute bars, for what values of `x`, is the expression `cos^2x*sinx` negative ?

OpenStudy (anonymous):

When x is pi/2 to 3pi/2

ganeshie8 (ganeshie8):

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