Question

fermentation is a complex chemical process of wine making in which glucose is converted into Ethanol and carbon dioxide. C6H12O6 -> C2H5OH + 2CO2 . starting with 925.1 g of glucose , what is the maximum amount of ethanol in GRAMS and LITRES that can be obtained by this process (density of ethanol=0.789g/mol)

Answer 1

First Step: you balance the chemical equation.
Second step: convert grams of glucose to moles of glucose
Third step: use mole ratio starting from oles of glucose to get moles of ethanol
Fifth step: convert moles of ethanol to grams of ethanol by using the molar mass of ethanol
Last step: use the given density to convert grams of ethanol to liters of ethanol

(note: I think there's a typo in the density of ethanol=0.789g/mol)
\(\Large \bf Density=\frac{g}{ml}\)
\(\Large \bf Density\neq \frac{g}{mols}\)

Therefore, density of ethanol=0.789g/ml not ethanol=0.789g/mol

Answer 2

FIRST STEP ; C6H12O6 -> 2C2H5OH + 2CO2
2ND STEP : 925.1 g / 180.1559 g = 5.1349970 molesof glucose
3RD STEP : 1 mole of glucose -> 2 moles of ethanol
5TH STEP ; g= 2 moles x 46. 068 44 g = 92.13688 g
last step ; ml = 92. 13688 g / 0.789 = 116.7767807 ml

thus , 92 g of ethanol with 116.8 ml of ethanol ..
thank you for showing me the step! helps me a lot!
yah, typo's there! thank you for telling!
i hope i get the correct step !

Answer 3

@Zale101 :)

Answer 4

can i just ask other question here? @Zale101 ?

Answer 5

i meant to write fourth step instead of fifth step xD

Answer 6

what you did looks good :)