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OpenStudy (anonymous):
Simplify.square root 27/12 will give metal
A.-3/2
B.2/3
C.3/2
D.3
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pooja195 (pooja195):
Can that be simplified?
pooja195 (pooja195):
27/12
OpenStudy (anonymous):
yes
pooja195 (pooja195):
To what?
OpenStudy (astrophysics):
\[\sqrt{\frac{ 27 }{ 12 }} \implies \left( \frac{ 27 }{ 12 } \right)^{1/2} = \frac{ 27^{1/2} }{ 12^{1/2} }\]
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OpenStudy (misty1212):
HI!!
OpenStudy (anonymous):
Hi misty
pooja195 (pooja195):
Wow that just looks like a mess now.
OpenStudy (astrophysics):
\[\implies \frac{ \sqrt{27} }{ \sqrt{12} } = \frac{ 3\sqrt{3} }{ 2\sqrt{3} }\]
OpenStudy (misty1212):
first step is to note that
\[\frac{27}{12}=\frac{9}{4}\] then take teh square root of the top and bottom separately
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OpenStudy (astrophysics):
Should get used to the exponent rules
OpenStudy (mertsj):
\[\sqrt{\frac{27}{12}}=\sqrt{\frac{9\times3}{4\times3}}=\sqrt{\frac{9}{4}}=\frac{\sqrt{9}}{\sqrt{4}}=\frac{3}{2}\]
OpenStudy (misty1212):
forget the fractional exponents, they do not help your cause at all
reduce first, take the square root last
OpenStudy (astrophysics):
No, don't forget just know there's more then one way of doing it, and all you have to do is cancel out the sqrt(3)'s
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