Question

1.
Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symmetry and extrema (if any) for the graph of this equation. Include a screen shot of the graph.

Answer 1

\[f(x)=\frac{ 3 }{ x^2-4 }+1\]

Answer 2

what part of question ,is your problem ?

Answer 3

2.
Explain
why
there
are
asymptotes
for
this
graph
and
how
to
find
them
algebraically.
Use
vocabulary
given
in
the
text
for
this
module.
3.
Algebraically
calculate
the
intercepts,
both
x
and
y.
Show
all
work
and
state
extraneous
solutions,
if
any.

Answer 4

\[vertical-retrice\rightarrow x^-4=0 \rightarrow x=\pm 2\\ \lim_{x \rightarrow 2}f(x)=\lim_{x \rightarrow 2}\frac{3}{x^2-4}+1=\infty \\so\\x=2 \space is-vertical-as.\\lim_{x \rightarrow -2}f(x)=\lim_{x \rightarrow -2}\frac{3}{x^2-4}+1=\infty \\so\\x=-2 \space is-vertical-as.\]
\[\lim_{x \rightarrow \pm \infty}\frac{3}{x^2-4}+1\rightarrow 0+1=1 \rightarrow y=1 \\is\\horizontal-as.\]

Answer 5

can u number em so I know what to put for each number @amoodarya

Answer 6

this operation was for finding asymptotes

Answer 7

to find intercept
find the root(s) of f(x)=0
\[\frac{3}{x^2-4}+1=0\\\frac{3}{x^2-4}=-1\\x^2-4=-3\\x^2=1\\x=\pm1\]