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Chemistry 21 Online
OpenStudy (anonymous):

Calculate the pH of a solution prepared by mixing 10.0 mL 1.0 M NaOAc and 35.0 mL 0.4M HOAc. Ka = 1.8E-5

OpenStudy (abb0t):

start by writing down the balanced equilibrium equation.

OpenStudy (abb0t):

can you do that

OpenStudy (anonymous):

PH=4.47+, 397 =5.137 Where 4.47 is the -ve log Ka =pka And , 397 is log base/acid This is Handerson equation by which you can detrmine the ph of buffer solution

OpenStudy (anonymous):

PH=Pka + log [base]/[acid] It is used only for buffer solution. Your compounds are salt of conjugate base which is NaOCN And acid which is HOAC And this is buffer solution.

OpenStudy (vincent-lyon.fr):

The formula given above is ok, but the calculation is wrong. You should be able to manage this now.

OpenStudy (anonymous):

I think it is true , but if you have noticed something wrong , I'll be glade to learn it from you

OpenStudy (vincent-lyon.fr):

I mean the numerical values must be calculated again. pKa is not 4.47 and log [base]/[acid] is not +0.397

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