Question

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Answer 1

@aaronq can i please take just a few mintues of your time?!?!?!? Pleaase check my work.

Answer 2

This is how i did it.......
Given: 30Hz, t = 0.20sec, d = 12m
To find the velocity, i need to find the wavelength first. Since V = fXLambda
V = Displacement in distance/ Displacement in time
V = 12m/0.20sec
V = 60sec
Now that we have our Velocity of the wave, we can now substitute both the given and reseultant values into the Formula V= F X Lambda
Lambda = V/F
Lambda = 60m/sec/30Hz =
Lambda = 2
Therefore the wavelength is 2meters long.

To find the Number of Loops, we need to take the inverse of Frequency and plug-in what's already given to us.....so
F = N/Change in time
30 Hz (given)= N/0.20sec
0.20sec X 30 = N
6 = N
Therefore the number of loops are 6.

Answer 3

What is takes sec, is that suppose to be .20 sec?

Answer 4

already given to us...0.20sec

Answer 5

i've lablled all the given values at the top.

Answer 6

Ok I see, well in your question it didn't mention that so just making sure.

Answer 7

^_^

Answer 8

So you need to do \[v = f \lambda = (30 Hz)(12m) = 360 m/s\], good I see you have \[v = \frac{ \Delta d }{ \Delta t } \implies \Delta d = v \Delta t\] which is, \[\Delta d = (360m/s)(0.20s) = 72m\] so far you agree?

Answer 9

how did you come up with "12"

Answer 10

"is used to make waves in a rope 12m long", i though the length of the rope is 12m long -__-

Answer 11

Actually you maybe right

Answer 12

I guess I was reading it wrong and thought the wavelength is 12m but I guess the rope is!

Answer 13

ok so once i have the velocity and the displacement, do i foolow the same procedure to find the wavelength.......λ = F/V

Answer 14

So, we should use \[v = \frac{ \Delta d }{ \Delta t } = \frac{ 12m }{ 0.20s } = 60m/s\] this seems better, I think the question is just worded weirdly so it caused the confusion.

Answer 15

\[\lambda = \frac{ v }{ f } = \frac{ 60m/s }{ 30 Hz } = 2m\] that makes more sense

Answer 16

that's what i was wondering.........360m/sec.....that's like sound breaking speed!!! :")

Answer 17

Yeah it was a bit confusing when I was writing it out

Answer 18

yep that's what i got.....λ = 2m

Answer 19

Now you can just divide that by the length of the string, so we have \[\frac{ 12m }{ 2m } = 6\] that is our wavelength in the string

Answer 20

amount of wavelengths*

Answer 21

yep....that's right...i got the same.....but hey do you know the trick of solving these kinds of peoblems?!?!?!?!

Answer 22

There's no real trick, just this problem is worded oddly as you noticed haha

Answer 23

Lots of practice I suppose

Answer 24

no i'm talking in general....tho, cuz i see some of the next problems i have in the book seem kinds hard.....

Answer 25

is there any difference between solving for fixed end and free end?!?!??!?

Answer 26

There's no trick to it, just takes practice, read the question carefully, put all your knowns/ unkowns down and see what you can use :)

Answer 27

Well I would have to see the question to see what exactly you're asking

Answer 28

ok....Thank you sooooooooooooooomuch, Luv you to death....!!! Please stay cute!!! :")

Answer 29

Haha np :) have fun!