verify the trigonometric equation by substituting identities to match the right hand side with the left hand side:

(sinx / 1-cosx) + (sinx / 1+cosx) = 2cscx

Question

verify the trigonometric equation by substituting identities to match the right hand side with the left hand side:

(sinx / 1-cosx) + (sinx / 1+cosx) = 2cscx

wampominater · Answer

looks like this 
$$\frac{ sinx }{ 1-cosx } + \frac{ sinx }{ 1+cosx }=2cscx$$

been stuck on this forever...

maheshmeghwal9 · Answer

on left hand side
take L.C.M.

butterflydreamer · Answer

start with your left hand side :)
hint: You'll want put the two fractions over the same denominator .

wampominater · Answer

so, would i get them both under 1-cos^2x?

wampominater · Answer

over*

butterflydreamer · Answer

correct:)

maheshmeghwal9 · Answer

It Becomes
$$\frac{ sinx(1+cosx)+sinx(1-cosx) }{ \sin^2x }$$

wampominater · Answer

alright then do I distribute sin?

butterflydreamer · Answer

yyeeepp

butterflydreamer · Answer

distribute sinx :)

wampominater · Answer

$$\frac{ 2sinx }{ \sin^2x }$$
like this?

maheshmeghwal9 · Answer

yes

butterflydreamer · Answer

then from there, you can simplify the fraction and you'll get the answer (RHS) :)

wampominater · Answer

Ok so how do I simplify this, Sorry! this is where i have been stuck at.

butterflydreamer · Answer

oh you can divide the numerator and denominator by sinx

wampominater · Answer

so is it 2/sinx? And then just change it to csc?

butterflydreamer · Answer

likeee: |dw:1436251446732:dw|