Question

How can 1/3x – 2 = y and 1/4x + 11 = y be set up as a system of equations?
3y – x = –6
4y – x = 44
3y + x = –6
4y + x = 44
3y – 3x = –6
4y – 4x = 44
3y + 3x = –6
4y + 4x = 44

Answer 1

@ganeshie8

Answer 2

@Michele_Laino

Answer 3

convert them both to standard form.

Answer 4

for example, your first equation can be rewritten as follows:
\[\frac{x}{3} - 2 = y \to x - 6 = 3y\]
where I have multiplied both sides by 3

Answer 5

and thats all? @Michele_Laino @dirtydishr4g

Answer 6

yes!
Please multiply the both sides of your second equation by 4, what do you get?

Answer 7

Hint:
you should get this:
\[\frac{x}{4} + 11 = y \to x + 44 = 4y\]

Answer 8

I get x+44=4y

Answer 9

@Michele_Laino

Answer 10

that's right!

Answer 11

now, if I subtract x, I get:
\[x + 44 - x = 4y - x\]
please simplify

Answer 12

4y-x=44? @Michele_Laino

Answer 13

that's right!

Answer 14

now I do the same with your first equation:
\[x - 6 - x = 3y - x\]
please simplify

Answer 15

So the answer would be A? 3y – x = –6
4y – x = 44

Answer 16

that's right!

Answer 17

Thank you. @Michele_Laino

Answer 18

:)