Question

Which is an equation in point-slope form of the line that passes through the points (4,5) and (-3, -1)

Answer 1

We need to find the slope first so
\[\frac{ y_2-y_1 }{ x_2-x_1 }\]

Answer 2

Can you find the slope using that formula please? ^_^

Answer 3

\[11\frac{ ? }{ ? }-8\]

Answer 4

oops sorry! 11 over -8

Answer 5

Not quite I will set up the problem for you :)
\[\huge~\rm~\frac{ -1-5 }{ -3-4 }=slope\]

Answer 6

-6 over -7?

Answer 7

yes :)
Alright next step is to pick a point lets got with (4,5)
Are you fimilar with this formula?
\[\huge~\rm~y-y_1=m(x-x_1)\]

Answer 8

not really

Answer 9

\[\huge~\rm~y-y_1=m(x-x_1)\]
M=slope=6/7<--lets keep it positive : )
x1=4
y1=5
Can you sub in the values please? :)

Answer 10

5-5=6/7(4-4)

Answer 11

No quite we do not need to plug in the values for the varibles that have no number \[\huge~\rm~y-y_1=m(x-x_1)\]
M=slope=6/7<--lets keep it positive : )
x1=4
y1=5
\[\huge~\rm~y-5=\frac{ 6 }{ 7 }(x-4)\]

Answer 12

i suck at this stuff!

Answer 13

Thats all it is buddy! :) You are doing just fine

Answer 14

is that the answer? its not one of my choices

Answer 15

What are the choices?

Answer 16

Hello?

Answer 17

in here! sorry!

Answer 18

I can finish up :) looks like they left

Answer 19

y+1=6/5(x+3)
y+1=6/7(x+3)
y-1=6/7(x-3)
y+3=7/6(x+1)

Answer 20

oh ok the only problem is that they used the wrong point not hard to fix we always need to use the 2nd point so
(-3,-1)
and we get
y+1=6/7(x+3)
We get "+" because a negative and a negative touching each other make a postive :) understood?

Answer 21

i do! thank you! could you help me with a few more?

Answer 22

linear inequality graph

Which is an equation of the given line in standard form?

A.
–11x + 6y = –13

B.
–6x +11y = 13

C.
–6x + 11y = –13

D.
–6x + 7y = –17

Answer 23

wow i suck at standered for @Jaynator495

Answer 24

http://static.k12.com/calms_media/media/1312500_1313000/1312641/1/a94dac9fc928f74786ee171aa73293fef63d604c/HS_A1G2_S1_07_10_ART1.jpg

Answer 25

Cannot help because you are from k12, sorry about this... you can ask indirect questions but NO test questions...