Question

7

Answer 1

i say 5 million times since 110dB = 1X10^-1 w/m^2
whereas the 60dB = 1 X 10^-6w/m^2

difference = 1X10^-1 w/m^2 All Divided by 1 X 10^-6w/m^2
and you get 5 and 5 = 5,000,000w/m^2

Answer 2

@aaronq

Answer 3

@MrNood can you check my work?!?!?!?!?!

Answer 4

@Astrophysics

Answer 5

Well as before let me list the formula first \[\beta = 10 \log \frac{ I }{ I_0 }\]
so we want the intensity of the rock concert compared to the sound of a normal conversation which is \[\frac{ I_{rc} }{ I_{nc} }\] So we want \[\beta_{rc}-\beta _{nc}\] where rc represents rock concert, and nc is normal conversation.

Answer 6

50 thousand

Answer 7

\[10\log \frac{ I_{rc} }{ I_0 }-10\log \frac{ I{nc} }{ I_0 }\]

Answer 8

what is I/I0

Answer 9

so in this case, I = 110dB/60dB?!?!?!?!?!

Answer 10

\[I_0 = 10^{-12}W/m^2\]

Answer 11

threshold......oh i c

Answer 12

\[\large 110-60 = 10\log \frac{ I_{rc} }{ I_0 }-10\log \frac{ I_{nc} }{ I_0 }\] this is what we should have

Answer 13

Now solve for \[\frac{ I_{rc} }{ I_{nc} }\]

Answer 14

ok wait let me solve this way, then maybe i'll make my own smaller and shorter way to do the same qestion......cuz that's too long....

Answer 15

What do you mean?

Answer 16

You want to compare the intensities, you're given the decibel readings

Answer 17

So you should have a ratio, no units.