Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

find m∠A.

OpenStudy (anonymous):

OpenStudy (anonymous):

plz help

OpenStudy (taramgrant0543664):

You can use the formula a^2=c^2+b^2-2abcosA, just put your values in for a,b and c and solve for A

OpenStudy (anonymous):

can you help me plug them in ... im really confused :(

OpenStudy (taramgrant0543664):

So a=4, b=5 and c=2

OpenStudy (taramgrant0543664):

4^2=(5^2)+(2^2)-2(5)(2)cosA I realized in the second portion it should have been bc not ab

OpenStudy (taramgrant0543664):

16=25+4-20cosA 16=29-20cosA -13=-20cosA 0.65=cosA A=? Are you able to finish that?

OpenStudy (anonymous):

would divide 0.64 by cosA? if it is right im not really sure how to solve it

OpenStudy (taramgrant0543664):

Nope you have to do the inverse of the cosine function in order to get A by itself so: \[\cos ^{-1}(0.65)\]

OpenStudy (anonymous):

ohh... i know im gonna sound kinda dumb.. but how do you do the inverse?

OpenStudy (anonymous):

i dont mean to sound mean but can you give me the answer i only have couple of mins left ! im on a timed quiz

OpenStudy (taramgrant0543664):

It's 49.46

OpenStudy (anonymous):

thank you so much taramgrant ! really appreciate it :) :)

OpenStudy (taramgrant0543664):

No problem!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!