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OpenStudy (anonymous):
find m∠A.
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OpenStudy (anonymous):
OpenStudy (anonymous):
plz help
OpenStudy (taramgrant0543664):
You can use the formula a^2=c^2+b^2-2abcosA, just put your values in for a,b and c and solve for A
OpenStudy (anonymous):
can you help me plug them in ... im really confused :(
OpenStudy (taramgrant0543664):
So a=4, b=5 and c=2
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OpenStudy (taramgrant0543664):
4^2=(5^2)+(2^2)-2(5)(2)cosA
I realized in the second portion it should have been bc not ab
OpenStudy (taramgrant0543664):
16=25+4-20cosA
16=29-20cosA
-13=-20cosA
0.65=cosA
A=? Are you able to finish that?
OpenStudy (anonymous):
would divide 0.64 by cosA? if it is right im not really sure how to solve it
OpenStudy (taramgrant0543664):
Nope you have to do the inverse of the cosine function in order to get A by itself so:
\[\cos ^{-1}(0.65)\]
OpenStudy (anonymous):
ohh... i know im gonna sound kinda dumb.. but how do you do the inverse?
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OpenStudy (anonymous):
i dont mean to sound mean but can you give me the answer i only have couple of mins left ! im on a timed quiz
OpenStudy (taramgrant0543664):
It's 49.46
OpenStudy (anonymous):
thank you so much taramgrant ! really appreciate it :) :)
OpenStudy (taramgrant0543664):
No problem!
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