Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

differentiate y=(Inx)^squart root x Do not simplify answer

OpenStudy (anonymous):

\[y=(\ln x)^{\sqrt{x}}\]

zepdrix (zepdrix):

Hey Jess :) We can uhhh.. use logs I suppose, that should help

zepdrix (zepdrix):

So umm.. ya ya let's try that. Let's take the natural log of each side.\[\large\rm \ln y= \ln\left[(\ln x)^{\sqrt x}\right]\]

zepdrix (zepdrix):

Now we can apply our log rule to rewrite the right side,\[\large\rm \ln y=\sqrt{x} ~\ln\left[(\ln x)\right]\]And from there you'll apply product rule :) It's gonna get messy! Confused by any of that? :o

OpenStudy (anonymous):

im somewhat getting it

zepdrix (zepdrix):

So let's first `set up` our derivative so we understand how it's going to look.\[\large\rm \color{royalblue}{(\ln y)'}=\color{royalblue}{(\sqrt x)'}\ln(\ln x)+\sqrt x\color{royalblue}{\left[\ln(\ln x)\right]'}\]The blue stuff is what we need to differentiate.

zepdrix (zepdrix):

Product rule on the right, ya?

zepdrix (zepdrix):

Too much? :O Brain esplode?

OpenStudy (anonymous):

no im still here

zepdrix (zepdrix):

So then uhhh take some derivatives :) remember derivative of \(\large\rm \sqrt{x}\) ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!