fin area of shaded region, please help: http://prntscr.com/7q4orp
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OpenStudy (anonymous):
Hi again!
OpenStudy (anikate):
hi :D
OpenStudy (anonymous):
Since AO is equivalent to AB it is a isosocles triangle.
OpenStudy (anonymous):
SO from that we can calculate angle o and angle b are 40 degrees
OpenStudy (anonymous):
do you know the sector formula?
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OpenStudy (anonymous):
\[\frac{ x }{ 360 } \times \pi r^2\]
OpenStudy (anikate):
sorry if i dont respond sometimes, my connection is terrible. My computer is as far as possible away from our network router, literally at the other corner of the house. and parents dont want to spend money on a dual band network router.
OpenStudy (anonymous):
x would be 40, as we found angle O was 40. this means the shaded area is 40 degrees of the whole 360 degrees of the circle.
OpenStudy (anonymous):
You get me?
OpenStudy (anonymous):
so
\[\frac{ 40 }{ 360 } \times \pi 6^2\]
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OpenStudy (anonymous):
then
\[\frac{ 1 }{ 9 } \times 36 \]
OpenStudy (anonymous):
sorry 36 pi
OpenStudy (anonymous):
so then once you multiply 1/9 and 36, you get 4, which then would equal 4 pi