Can some explains this to meh. please?
Look at these sets of ordered pairs. W) {(8, 9), (2, 3), (0, -2), (10, -9)} X) {(0, 0), (5, 10), (-3, 3)} Y) {(1, 1), (2, 2), (3, 3), (4, 4)} Z) {(-10, 1), (-9, 3), (-4, 5)} Which of the sets represent functions?
W is a function because each of the x values (first values in each pair) has a different value of y associated with it
Z is also a function for the same reason
so what you are saying is that w and z are functions because x and y do not have the same values
Y maps on to itself - not sure but i think a function can do that.
hmmm
i hate to disgree with @welshfella but this is what you need to look at: if all the x values are distinct (all different) then it IS a function if there are repeated x values (some are the same) then it is NOT a function
ignore the y values completely they have nothing whatsoever to do with it
no a relation is a function if each value of x only maps on to a single value of y so a function can be one-to-one or many=to-one but it cant be one-to-many
\[W) \{(\color{red}8, 9), (\color{red}2, 3), (\color{red}0, -2), (\color{red}{10}, -9)\}\]
all x's are different, it IS a function
so {(3,1) (2,3) is a function but {(3,1) (3,4) is not a function (as its one-to-many)
so which values do i compare to tell if one value is a function itself
This is not my expertise but aren't they all functions?
so W,Y, and Z are the functions or is it all of them
yes you are right misty - my error
I think all of them are
I am sorry i am confused which ones are the functions and which ones are not?
all are
okay thank you @welshfella and thank you as well @misty1212
just check out the x values as misty said - they are all different in each function
I have trouble with functions on times.....
- you can have repetition of y values but not of x values so { (1,2), (2,2) } for example is a function because its many-to-one
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