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Mathematics 17 Online
OpenStudy (loser66):

Question in comment Please, help

OpenStudy (loser66):

1) Find the equation for the periodic function and its period|dw:1436381101289:dw|

OpenStudy (loser66):

2) find the Laplace transform of it

OpenStudy (loser66):

3) find the inverse laplace transform \(L^{-1}(\dfrac{k}{as+b})\) where k, a, b in R/{0} and are constants

OpenStudy (dan815):

they are giving you the constants on your continous power series, u have to see what that gives you in t domain

OpenStudy (loser66):

dan, how to know whether a differential equation linear or not?

OpenStudy (dan815):

no xy no y^2 and such

OpenStudy (loser66):

why not? since the linear differential equation standard form is \(y^{(m)} +P_1(x) y^{(m-1)}+..... = Q(x)\) Like y" +y' +xy =0. ??

OpenStudy (dan815):

no xy^2

OpenStudy (dan815):

that equation is linear

OpenStudy (dan815):

i was confused with linear form there

OpenStudy (dan815):

by the way the question you asked earlier, what did u get for this 1) Find the equation for the periodic function and its period

OpenStudy (loser66):

I didn't.

OpenStudy (dan815):

wheres your work so farq

OpenStudy (loser66):

dan, remember the previous post ? http://math.stackexchange.com/questions/1354551/finding-differential-equation-from-the-solution

OpenStudy (loser66):

Wow!!! they derive the problem into other way!! but it works also.

OpenStudy (loser66):

dan, honestly, I don't know how to work on it.

OpenStudy (loser66):

Since the slopes of the lines are equal, we have y'= 1 , that gives us y= x +a. But it doesn't make sense since y = x +a are family of vertical lines, not horizontal like this.

OpenStudy (loser66):

what I don't understand is here|dw:1436404165210:dw|

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