Mathematics
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OpenStudy (anonymous):
Evaluate |c 2 + b 2|, given a = 5, b = -3, and c = -2.
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OpenStudy (anonymous):
help?
OpenStudy (anonymous):
answer is 10
positive 10
you want an explanation?
OpenStudy (anonymous):
@.Gjallarhorn. yes please
OpenStudy (anonymous):
so since c=-2, you multiply -2 and 2 together. what do you get?
OpenStudy (anonymous):
-4? @.Gjallarhorn.
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OpenStudy (anonymous):
right now leave that off to the side and lets go to the other one
OpenStudy (anonymous):
since b=-3 you multiply -3 and 2 together and you get?
OpenStudy (anonymous):
-6
OpenStudy (anonymous):
good. now you gotta add both your results. so -4 + -6 =?
OpenStudy (anonymous):
making it positive 10
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OpenStudy (anonymous):
good try but no. -4+ -6= -10
OpenStudy (anonymous):
but thats not our final answer. so you see how the equation has a line like this? >> |
OpenStudy (anonymous):
on both sides?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
that means whatever you get inside those lines, is measured as a distance from 0
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OpenStudy (anonymous):
how many units away it is from 0.
OpenStudy (anonymous):
oh i thought it was the negatives canceiling each other out >.<
OpenStudy (anonymous):
so in |-6|
-6 is 6 units away from 0. so your answer would be six in a question like this
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
thats just an example
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OpenStudy (anonymous):
so how many units is -10 away from 0?
OpenStudy (anonymous):
10 units
OpenStudy (anonymous):
right. so these are always positive. 10 is your answer . good job
OpenStudy (anonymous):
thanks
OpenStudy (jdoe0001):
hmm \(\large |c^2 + b^2|\qquad
\begin{cases}
a=5\\b=-3\\c=-2
\end{cases}\qquad ?\)
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OpenStudy (anonymous):
no prob