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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate |c 2 + b 2|, given a = 5, b = -3, and c = -2.

OpenStudy (anonymous):

help?

OpenStudy (anonymous):

answer is 10 positive 10 you want an explanation?

OpenStudy (anonymous):

@.Gjallarhorn. yes please

OpenStudy (anonymous):

so since c=-2, you multiply -2 and 2 together. what do you get?

OpenStudy (anonymous):

-4? @.Gjallarhorn.

OpenStudy (anonymous):

right now leave that off to the side and lets go to the other one

OpenStudy (anonymous):

since b=-3 you multiply -3 and 2 together and you get?

OpenStudy (anonymous):

-6

OpenStudy (anonymous):

good. now you gotta add both your results. so -4 + -6 =?

OpenStudy (anonymous):

making it positive 10

OpenStudy (anonymous):

good try but no. -4+ -6= -10

OpenStudy (anonymous):

but thats not our final answer. so you see how the equation has a line like this? >> |

OpenStudy (anonymous):

on both sides?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

that means whatever you get inside those lines, is measured as a distance from 0

OpenStudy (anonymous):

how many units away it is from 0.

OpenStudy (anonymous):

oh i thought it was the negatives canceiling each other out >.<

OpenStudy (anonymous):

so in |-6| -6 is 6 units away from 0. so your answer would be six in a question like this

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

thats just an example

OpenStudy (anonymous):

so how many units is -10 away from 0?

OpenStudy (anonymous):

10 units

OpenStudy (anonymous):

right. so these are always positive. 10 is your answer . good job

OpenStudy (anonymous):

thanks

OpenStudy (jdoe0001):

hmm \(\large |c^2 + b^2|\qquad \begin{cases} a=5\\b=-3\\c=-2 \end{cases}\qquad ?\)

OpenStudy (anonymous):

no prob

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