Question

Find the magnitude & direction of the vector JK given points J(1,0) & K(-2,3).

Answer 1

First we need to find the vector in <x,y> form

Subtract the corresponding coordinates (tail - head)

x = -2 - 1 = -3
y = 3 - 0 = 3

the vector JK is <-3, 3>

now you will use the formula sqrt(x^2 + y^2) to get the magnitude

to get the direction, use arctan(y/x). The angle is in Q2, so you'll have to add 180 degrees

Answer 2

\(\large u=<a,b>\qquad
\begin{cases}
magnitude\implies \sqrt{a^2+b^2}\\
direction\implies tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\)

Answer 3

wait im kinda confused

Answer 4

where are you stuck?

Answer 5

nevermind i got it thanks