Algebra
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OpenStudy (anonymous):
Find the Quotient of 20x^2y-88xy/-4xy
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jimthompson5910 (jim_thompson5910):
The problem is this, right?
\[\Large \frac{20x^2y-88xy}{-4xy}\]
OpenStudy (anonymous):
Yes
jimthompson5910 (jim_thompson5910):
we can factor out -4xy from the numerator
\[\Large \frac{20x^2y-88xy}{-4xy} = \frac{-4xy(-5x+22)}{-4xy} \]
what comes next?
OpenStudy (anonymous):
I'm having a very hard time understanding even from the beginning, if you can i would love for you to help explain it to me.
jimthompson5910 (jim_thompson5910):
well I factored out -4xy because that's what is in the denominator
I want to cancel out the denominator
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jimthompson5910 (jim_thompson5910):
did you learn about factoring yet?
OpenStudy (anonymous):
i believe so but I'm not positive
jimthompson5910 (jim_thompson5910):
the idea of factoring is to rewrite a number or expression as a product of two smaller things
jimthompson5910 (jim_thompson5910):
ex:
27 = 9*3
16 = 8*2
OpenStudy (anonymous):
could possibly be 22x^2y^2+20x^2y
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jimthompson5910 (jim_thompson5910):
what do you mean?
OpenStudy (anonymous):
for the awnser i asked my mom and she said she thinks that is what it is
jimthompson5910 (jim_thompson5910):
have you learned about the distributive property?
OpenStudy (anonymous):
is that not with (X)^Y
jimthompson5910 (jim_thompson5910):
it's something like
2*(x+y) = 2*x + 2*y
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OpenStudy (anonymous):
yeah i have
jimthompson5910 (jim_thompson5910):
so when I factored back up at the top, I used the distributive property (in reverse)
jimthompson5910 (jim_thompson5910):
if you have 2*x + 2*y
you can factor out 2 to get 2*(x+y)
jimthompson5910 (jim_thompson5910):
same idea with your problem, but I pulled out -4xy
OpenStudy (anonymous):
okay im some what following lol
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jimthompson5910 (jim_thompson5910):
it turns out that -4xy is a common factor of 20x^2y and -88xy
jimthompson5910 (jim_thompson5910):
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