Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?
(x − 2)2 + (y + 3)2 = 5

(x + 2)2 + (y − 3)2 = 25

(x − 2)2 + (y + 3)2 = 25

(x − 2)2 − (y + 3)2 = 5

Answer 1

standard form is (x-h)^2 + (y-k)^2 = r^2

where (h,k) is the centre and r is the radius

Answer 2

i dont understand how to do it

Answer 3

Is it the third one?

Answer 4

centre is (2,-3) so h=2 and k = -3

Answer 5

So the second one

Answer 6

if you substitute the h and k values you get (x-2)^2 +(y+3)^2 = r^2
so now you have to work out the radius r

Answer 7

i'll let you do that

Answer 8

25

Answer 9

So the second one

Answer 10

the radius is the distance between the two points, which is?