Question

Determine in which direction the parabola below opens.

y = -2x^2 + 5x - 2

Answer 1

@SoulEater142

Answer 2

Ok, here:
~ b and c can be any negative or positive real numbers (or can be zero).
~ a is a positive number that can't be equal to zero (and thus -a is a negative number)
`----------------------------`


`UP/DOWN opening parabolas.`

If you have
\(\large\color{black}{ \displaystyle y=ax^2+bx+c }\)
then, this parabola opens UP

If you have
\(\large\color{black}{ \displaystyle y=-ax^2+bx+c }\)
then, this parabola opens DOWN



`LEFT/RIGHT opening parabolas.`

If you have
\(\large\color{black}{ \displaystyle x=-ay^2+by+c }\)
then, this parabola opens to the LEFT

If you have
\(\large\color{black}{ \displaystyle x=ay^2+by+c }\)
then, this parabola opens to the RIGHT

Answer 3

do you want some real (not abstract) examples?

Answer 4

Im confused so the answer is right???

Answer 5

here is some help

Answer 6

yeah don those were what I meant his examples is a negative the other one was positive.

Answer 7

ohh so am i correct in saying that the answer is UP?

Answer 8

yes

Answer 9

I will give you some examples.


OPENS UP (examples)
\(\large\color{black}{ \displaystyle y=x^2-4x+2 }\)
\(\large\color{black}{ \displaystyle y=0.2x^2-18 }\)
\(\large\color{black}{ \displaystyle y=19x^2+6x }\)
\(\large\color{black}{ \displaystyle y=3x^2+3x+3 }\)
(as long as that number in front of x² is positive)

OPENS DOWN (examples)
\(\large\color{black}{ \displaystyle y=-x^2 }\)
\(\large\color{black}{ \displaystyle y=-0.01x^2+200 }\)
\(\large\color{black}{ \displaystyle y=-9x^2-17x }\)
\(\large\color{black}{ \displaystyle y=-5x^2+3x-7 }\)
(as long as that number in front of x² is negative)