How to find the angle measure of T?
I have no idea how to solve this since there's no other angle measure
Try the law of cosines. Do you know it?
Here is the Law of Cosines
@wolf1728 are you sure thats it? i thought it was a^2=b^2+c^2-2bc cosa ???
In your problem, let the three sides be t=7, r=11, s=10. Then the law of cosines becomes\[t ^{2}=r ^{2}+s ^{2}-2rs \cos \left( T \right)\]
ospreytriple's equation is better to use because itis written in terms of r, s and t
@ospreytriple would i just plug in the numbers from the triangle???
Rearranging, you get\[T=\cos ^{-1}\left(\frac{ r ^{2} +s ^{2}-t ^{2}}{ 2rs }\right)\]
@ospreytriple i'm really confused on how i would get a real answer out of that equation :(
just plug in the lengths of sides r, s, & t from the triangle.
@ospreytriple oh okay that's what i was wondering lmao
What do you get for an answer?
@ospreytriple 45.57
Not what I get. You want to try it again?
@ospreytriple i got 63.25 :(
@ospreytriple i got 63.25 :(
@ospreytriple T=10? r=7? s=11?
No. t=10. You are trying to find angle T.
briana r^2 = 121 s^2 = 100 t^2 = 49 r^2 + s^2 -t^2 = 172 agreed?
I think having 2 people explain things to a third gets a bit confusing good luck briana and osprey :-)
@ospreytriple i listed those numbers because those are the ones you substitute in, right??
Ok. Evaluate the above equation for T by using the values of r, s, & t from the triangle.
@ospreytriple i know but i'm just asking if those are the numbers i use ??? like those are the correct ones for the substitution
I believe those are the side lengths from the triangle, yes.
\[T=\cos ^{-1}\left( \frac{ 11^{2}+10^{2} -7^{2}}{ 2\left( 11 \right)\left( 10 \right) } \right)\]
@ospreytriple yeah i jsut did that and my answer came out to be 63.25 again
What do you get for the value of the numerator?
@ospreytriple 70
Not quite.\[11^{2}+10^{2}-7^{1}=121+100-49= ?\]
Should be 7^2. Sorry.
@ospreytriple oh oops 172
Great. Now the denominator is\[2\left( 11 \right)\left( 10 \right)=?\]
@ospreytriple 220
Terrific so\[T=\cos ^{-1}\left( \frac{ 172 }{ 220 } \right)=?\]
@ospreytriple the calculator i'm using says 63.25???
@ospreytriple wait nevermind 38.64
Now you got it. Good job.
@ospreytriple sorry fro taking so long :( this unit is really messing me up
You're welcome. Those pesky calculators :)
Join our real-time social learning platform and learn together with your friends!