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Mathematics 22 Online
OpenStudy (briana.img):

How to find the angle measure of T?

OpenStudy (briana.img):

I have no idea how to solve this since there's no other angle measure

OpenStudy (anonymous):

Try the law of cosines. Do you know it?

OpenStudy (wolf1728):

Here is the Law of Cosines

OpenStudy (briana.img):

@wolf1728 are you sure thats it? i thought it was a^2=b^2+c^2-2bc cosa ???

OpenStudy (anonymous):

In your problem, let the three sides be t=7, r=11, s=10. Then the law of cosines becomes\[t ^{2}=r ^{2}+s ^{2}-2rs \cos \left( T \right)\]

OpenStudy (wolf1728):

ospreytriple's equation is better to use because itis written in terms of r, s and t

OpenStudy (briana.img):

@ospreytriple would i just plug in the numbers from the triangle???

OpenStudy (anonymous):

Rearranging, you get\[T=\cos ^{-1}\left(\frac{ r ^{2} +s ^{2}-t ^{2}}{ 2rs }\right)\]

OpenStudy (briana.img):

@ospreytriple i'm really confused on how i would get a real answer out of that equation :(

OpenStudy (anonymous):

just plug in the lengths of sides r, s, & t from the triangle.

OpenStudy (briana.img):

@ospreytriple oh okay that's what i was wondering lmao

OpenStudy (anonymous):

What do you get for an answer?

OpenStudy (briana.img):

@ospreytriple 45.57

OpenStudy (anonymous):

Not what I get. You want to try it again?

OpenStudy (briana.img):

@ospreytriple i got 63.25 :(

OpenStudy (briana.img):

@ospreytriple i got 63.25 :(

OpenStudy (briana.img):

@ospreytriple T=10? r=7? s=11?

OpenStudy (anonymous):

No. t=10. You are trying to find angle T.

OpenStudy (wolf1728):

briana r^2 = 121 s^2 = 100 t^2 = 49 r^2 + s^2 -t^2 = 172 agreed?

OpenStudy (wolf1728):

I think having 2 people explain things to a third gets a bit confusing good luck briana and osprey :-)

OpenStudy (briana.img):

@ospreytriple i listed those numbers because those are the ones you substitute in, right??

OpenStudy (anonymous):

Ok. Evaluate the above equation for T by using the values of r, s, & t from the triangle.

OpenStudy (briana.img):

@ospreytriple i know but i'm just asking if those are the numbers i use ??? like those are the correct ones for the substitution

OpenStudy (anonymous):

I believe those are the side lengths from the triangle, yes.

OpenStudy (anonymous):

\[T=\cos ^{-1}\left( \frac{ 11^{2}+10^{2} -7^{2}}{ 2\left( 11 \right)\left( 10 \right) } \right)\]

OpenStudy (briana.img):

@ospreytriple yeah i jsut did that and my answer came out to be 63.25 again

OpenStudy (anonymous):

What do you get for the value of the numerator?

OpenStudy (briana.img):

@ospreytriple 70

OpenStudy (anonymous):

Not quite.\[11^{2}+10^{2}-7^{1}=121+100-49= ?\]

OpenStudy (anonymous):

Should be 7^2. Sorry.

OpenStudy (briana.img):

@ospreytriple oh oops 172

OpenStudy (anonymous):

Great. Now the denominator is\[2\left( 11 \right)\left( 10 \right)=?\]

OpenStudy (briana.img):

@ospreytriple 220

OpenStudy (anonymous):

Terrific so\[T=\cos ^{-1}\left( \frac{ 172 }{ 220 } \right)=?\]

OpenStudy (briana.img):

@ospreytriple the calculator i'm using says 63.25???

OpenStudy (briana.img):

@ospreytriple wait nevermind 38.64

OpenStudy (anonymous):

Now you got it. Good job.

OpenStudy (briana.img):

@ospreytriple sorry fro taking so long :( this unit is really messing me up

OpenStudy (anonymous):

You're welcome. Those pesky calculators :)

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