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Mathematics 17 Online
OpenStudy (briana.img):

Find the value of a .

OpenStudy (briana.img):

I seriously just did a problem like this but I always forgot on how to use it

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

looks like a law of cosines problem?

OpenStudy (anonymous):

sine law again.

OpenStudy (misty1212):

hmm i think you need cosines for this you do not know any angle opposite one of the known sides

OpenStudy (anonymous):

right you are. Cosine law required.

OpenStudy (briana.img):

\[\frac{ \sin52 }{ ? } = \frac{ sinb }{ 4 }\]

OpenStudy (misty1212):

\[a^2=b^2+c^2-2bc\cos(A)\] \[a^2=4^2+7^2-2\times 4\times \cos(52^\circ)\] and a calcullator

OpenStudy (misty1212):

hold the phone dear

OpenStudy (misty1212):

if you want to use the law of sines (which you do , because it is easiest) you need 3 out of the for numbers to make a ratio

OpenStudy (misty1212):

you do not have three out of any four, because you do not know the angle opposite any known side

OpenStudy (misty1212):

you can see you ran in to that problem when you wrote \[\frac{ \sin52 }{ ? } = \frac{ \sin(b) }{ 4 }\]

OpenStudy (misty1212):

you got only two of the four numbers, two are unknown so you must use the law of cosines for this one

OpenStudy (briana.img):

@misty1212 i got 5.52507014 from doing your way after square rooting

OpenStudy (misty1212):

i can check if you like, i didn't do it

OpenStudy (briana.img):

@misty1212 i think it's right but can you check it please

OpenStudy (misty1212):

5.52 rounded looks good

OpenStudy (briana.img):

@misty1212 could you help me with another problem? please

OpenStudy (misty1212):

or in your case 5.5 cause they rounded to one decimal place

OpenStudy (misty1212):

yeah but i can't read what they are trying to find the value of in this case you know two angles so you know all three and therefore you can use the law of sines

OpenStudy (misty1212):

what do they want, \(r\) ?

OpenStudy (briana.img):

@misty1212 trying to find the value of r which is reallyw eird

OpenStudy (misty1212):

ok what is the measure of the angle opposite \(r\)?

OpenStudy (briana.img):

@misty1212 there's no angle opposite of r that's the weird part

OpenStudy (misty1212):

of course there is lol

OpenStudy (misty1212):

it is labelled \(\huge R\)

OpenStudy (briana.img):

@misty1212 there isn't!!

OpenStudy (misty1212):

oh i see, you mean you don't know what it is

OpenStudy (misty1212):

lets find it total in the triangle is 180 so it is \[180-45-63=72\]

OpenStudy (briana.img):

@misty1212 oooh yeah lmao forgot you could do it like that

OpenStudy (misty1212):

now law of sines finishes it right?

OpenStudy (misty1212):

\[\frac{r}{\sin(72)}=\frac{22}{\sin(45)}\] etc

OpenStudy (briana.img):

@misty1212 so it's rearrange to 22sin72=rsin45?

OpenStudy (misty1212):

this time i notice they round to two places http://www.wolframalpha.com/input/?i=22sin%2872%29%2Fsin%2845%29

OpenStudy (misty1212):

that step is not necessary

OpenStudy (misty1212):

\[\frac{r}{\sin(72)}=\frac{22}{\sin(45)}\iff r=22\times\frac{ \sin(72)}{\sin(45)}\]

OpenStudy (misty1212):

i know some math teacher might have said "cross multiply" but they are silly \[\frac{x}{a}=\frac{b}{c}\iff x=\frac{ab}{c}\]

OpenStudy (briana.img):

@misty1212 r=29.58993453?

OpenStudy (misty1212):

yeah looks good

OpenStudy (briana.img):

@misty1212 thank you!!! you really helped me tonight htis lesson really got me messed up

OpenStudy (misty1212):

you're welcome!\[\huge \color\magenta\heartsuit\]

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