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What can you add to x^2 - 22 to make it a perfect square trinomial
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Do you type this correctly? There is no real number that you can square to to get a negative 22. So if you typed the question correctly you would have to use an imaginary number and square it to get -22. So the middle term would be 2xi*22^(1/2)
You previous post shows X^2-22x (x+b)^2 = x^2 +2bx+b^2 So you need to find what b^2 equals. But you know the second term is -22x, so from that you can find the value of b and then just square to find your third term.
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