Question

math

Answer 1

How did they come up with that "*" portion?

Answer 2

i dont understand the Png you have attached

Answer 3

The * portion is the last step in integrating the given problem

Answer 4

its 12 s

Answer 5

*****
\[\large\int\limits_0^s\frac{\mathrm ds}{\sqrt{12s+0.02s^2}}=\int\limits_0^t\mathrm dt\]

Answer 6

yes =)

Answer 7

whats the original question?

Answer 8

The one that @UnkleRhaukus wrote

Answer 9

oh, i thought those integrals were derived from some differential equation...

Answer 10

Let \(u = \sqrt{12s+0.02s^2}\)
\(\mathrm du = (\cdots)\mathrm ds\)