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***WILL MEDAL*** divide. \[\frac{ 8y ^{2}-4y+1 }{ 2y-1 }\]
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divide 8/2 and subtract the exponents \[y ^{2-1}\]
@Falling_In_Katt ?
I would have thought that long division was in order
4y^1?
you can just put \(4y\)
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now -4/2
-2
and \(\dfrac{y}{y}\)
\(y^{1-1}\)
y^0
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so y cancels out \(4y-2\)
last step \(\dfrac{-1}{1}\)
actually the other way \(\dfrac{1}{-1}\) doesn't really matter
-1
so your answer is \(4y-2-1\)
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oh okay. thank you!
combine -2 - 1 \(4y-3\)
and yw
No way. That's not right
The correct answer using polynomial long division is 4y + 1/(2y-1)
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