What are the amplitude, period, phase shift, and midline of f(x) = -3 sin(4x - π) + 2? (5 points)
@Owlcoffee
what do you think the amp is?
that is all you really have to know to get this question
how do i find it
oh I thought you would know how because it is the easiest thing to find it is the absolute value of the constant number being multiplied to the trig function there
so 3?
yep
you are done because there is only one option with amp=3
lol yay thanks
in any trigonometric equality with the form: \[y=Asin(ax+ \alpha) \] The amplitude is the number "A" and you can calculate the period with: \[p=\frac{ 2 \pi }{ a }\]
you mean the amp=|A|?
\[y=A \sin(bx+c)+d \\ \text{ amp } =|A| \\ \text{ period } =\frac{2 \pi}{|b|} \\ \\ \text{ phase shift : } \text{ solve for } x : bx+c=0 \\ \text{ max if } A \text{ is } \text{ positive is } A(1)+d=A+d \\ \text{ min if } A \text{ is } \text{ positive is } A(-1)+d=-A+d \\ \text{ so the average the of max and min is }=\frac{(A+d)+(-A+d)}{2}=\frac{2d}{2}=d \\ \text{ the midline is therefore } y=d\]
thank you for all of that
was my answer correct for the other 1?
oh yep you can apply the same information I just gave to that one you have period is 2pi 2pi=2pi/|b| means |b|=1 which means b=-1 or b=1 phase shift (think horizontal shift): solve inside=0 to get phase shift and as you see x-pi=0 gives x=pi so pi is the phase shift the vertical shift is yes the number hanging outside the d=-4
yay thank you :)
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