Question

PLEASE HELP I WILL MEDAL!
What is the standard form of equation of a circle with center at (-2, -3) and passing through the point (-2, 0)?
A. (x + 2)^2 + (y + 3)^2 = 9
B. (x − 2)^2 + (y − 3)^2 = 16
C. (x − 2)^2 + (y − 3)^2 = 4
D. (x + 2)^2 + (y + 3)^2 = 16
E. (x − 2)^2 + (y + 3)^2 = 9

Answer 1

@peachpi

Answer 2

@joyraheb

Answer 3

What's the distance between the points (-2, 0) and (-2, 3)? That distance will be the radius.

Answer 4

4?

Answer 5

no, the x's are the same, so we can just subtract the y's.
r = 0 - (-3) = 3

Answer 6

now just plug into the formula

(x - h)² + (y - k)² = r²
(h, k) is (-2, -3) the center

Answer 7

(x-2)^2 +(y-3)^2=9

Answer 8

do i switch them to addition since they were already negatives?

Answer 9

yes you have to switch them

Answer 10

so its A

Answer 11

yes

Answer 12

thank you

Answer 13

you're welcome