Question

Simplify the equation. Then solve by the quadratic formula..

Answer 1

3x^2-4x+3=0

Answer 2

\[3x^2+(-4)x+3=0 \\ \text{ compare this to } \\ ax^2+bx+c=0\]
what does a,b,c have to equal ?

Answer 3

x= -(-4)+- square root (-4)^2 -4(3)(3)/2(3)

Answer 4

\[a=3,b=-4,c=3 \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ x=\frac{-(-4) \pm \sqrt{(-4)^2-4(3)(3)}}{2(3)}\]
is correct so far

Answer 5

-(-4)=?
(-4)^2=?
4(3)(3)=?
2(3)=?

Answer 6

4+square root 16-36/6

4+- square root -20/6

Answer 7

Please dont talk down to me. Im in college. Im just trying to figure out where I went wrong.

Answer 8

\[x=\frac{4 \pm \sqrt{16-36}}{6} \\ x=\frac{4 \pm \sqrt{-20}}{6}\]
that is also correct so far

Answer 9

who is talking down to you?

Answer 10

Any question I ask on the math group does..

Answer 11

my example says to do this--

Answer 12

I don't know where I was talking down to you at but sorry . I will stop trying to help.

Answer 13

6(4+-4i square root)/6 cancel out the 6

Answer 14

Sorry I wasnt saying you were I was say please dont do what others have

Answer 15

6(4+-4i square root 5)/6 cancel out the 6

Answer 16

My final answer is 4+-2i square root 5 but its wrong