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Mathematics 18 Online
OpenStudy (destinyyyy):

Simplify the equation. The solve by the quadratic formula.

OpenStudy (destinyyyy):

x(x+6)=-54

OpenStudy (destinyyyy):

x^2+6x=-54 x^2+6x+54=0 -(6)+- square root (6)^2 -4(1)(54)/2(1) -6+- square root 36-216/2 -6+- square root -180/2

OpenStudy (destinyyyy):

-6+- square root 9*20/2 -6+- 3i square root 20/2

OpenStudy (destinyyyy):

Im stuck there.

OpenStudy (destinyyyy):

Yes there is.. The final answer is -3+-3i square root 5

rishavraj (rishavraj):

see yeah theres solution

rishavraj (rishavraj):

see D = -180 so \[x = \frac{ -6 \pm \sqrt{-180} }{ 2 }\]

OpenStudy (destinyyyy):

Yes.

OpenStudy (destinyyyy):

Wow thanks for not helping.

jimthompson5910 (jim_thompson5910):

hint: \[\Large \sqrt{20} = \sqrt{4*5}\] \[\Large \sqrt{20} = \sqrt{4}*\sqrt{5}\] \[\Large \sqrt{20} = 2*\sqrt{5}\]

OpenStudy (destinyyyy):

What???

jimthompson5910 (jim_thompson5910):

You got to \[\Large x = \frac{-6 \pm 3i\sqrt{20}}{2}\]

OpenStudy (destinyyyy):

Yes..

jimthompson5910 (jim_thompson5910):

the root 20 can be replaced \[\Large x = \frac{-6 \pm 3i*\sqrt{20}}{2}\] \[\Large x = \frac{-6 \pm 3i*{\color{red}{\sqrt{20}}}}{2}\] \[\Large x = \frac{-6 \pm 3i*{\color{red}{2\sqrt{5}}}}{2}\]

jimthompson5910 (jim_thompson5910):

then you can factor out 2 from the numerator and cancel the '2's

OpenStudy (destinyyyy):

Then that would leave me with -6+- 3i square root 5

jimthompson5910 (jim_thompson5910):

you factor out 2 from the -6 as well \[\Large x = \frac{-6 \pm 3i*2\sqrt{5}}{2}\] \[\Large x = \frac{2(-3 \pm 3i\sqrt{5})}{2}\]

OpenStudy (destinyyyy):

Okay.. So I didnt mess up any where.. Thank you @jim_thompson5910

jimthompson5910 (jim_thompson5910):

you're welcome

jimthompson5910 (jim_thompson5910):

I think you meant to say `-3+- 3i square root 5` if so then you are correct since the answers are \[\Large x = -3\pm3i\sqrt{5}\]

OpenStudy (destinyyyy):

Yes I did

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