Question

convert 0.004 g/(min.)(m^3)cm to lbm/(hr)(ft^3)

Answer 1

can you help me @ganeshie8 and @Michele_Laino :) i can do it if the given is g/(min.)(m^3) ,but there's a cm in the denominator :/

Answer 2

is your measure like this?
\[\Large 0.04\frac{g}{{\min \times {m^3} \times cm}}\]

Answer 3

yes :)

Answer 4

"lbm" stands for?

Answer 5

pound (mass)

Answer 6

g stands for grams? right?

Answer 7

yes :)

Answer 8

please wait, I'm working on your question

Answer 9

it's okay and take your time, thank you for helping me :)

Answer 10

please note that, in the first unit measure, we divide by a length^4
whereas in the second unit of measure we divide by a length^3

Answer 11

since the second unit of measure is:
\[\Large \frac{{{\text{lbm}}}}{{{\text{hour}} \cdot {\text{ fee}}{{\text{t}}^{\text{3}}}}}\]

Answer 12

uhmm i'm sorry I didn't quite get it about dividiing by a length^4 part, can you show it to me. i'm really sorry :(

Answer 13

the first unit of measure is:
\[\Large \frac{{{\text{grams}}}}{{{\text{min }} \times {{\text{m}}^{\text{3}}}{\text{ }} \times {\text{cm}}}}{\text{ = }}\frac{{{\text{mass}}}}{{{\text{time }} \times {\text{lengt}}{{\text{h}}^{\text{4}}}}}\]

Answer 14

m stands for meter, right?

Answer 15

yes :)

Answer 16

so:
m^3*cm = length^4

Answer 17

\[4x10^-5 kg/(\min)(m^4) \times 60 \min./1hr \times 1lbm/0.4536 kg \times (0.3048m)^3/1ft.^3\]

Answer 18

so, there is not cm at the denominator?

Answer 19

oops sorry i'll do it again i forgot to convert cm to m. am I doing it right?

Answer 20

nope, it says on our worksheet that it's placed in the denominator :(

Answer 21

if the dimensions are not equal, we can not change from one unit of measure to another

Answer 22

maybe there is m^2 instead of m^3?

Answer 23

i'll just ask my professor about this quetion, maybe it's a typographical error, it would be easier if cm is not present in the question :)))

Answer 24

ok!

Answer 25

thank you so much for helping me :D

Answer 26

:)