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Geometry 24 Online
OpenStudy (anonymous):

I need help on this, please? The vertices of a triangle are A(7, 5), B(4, 2), and C(9, 2). What is m? A. 30° B. 45° C. 56.31° D. 78.69°

OpenStudy (misty1212):

HI!!

OpenStudy (anonymous):

hey

OpenStudy (misty1212):

that is a good question, what is \(m\)? not clear at all since none of the vertices are labelled "m"

OpenStudy (anonymous):

<ABC?* this was missing in the whole question, sorry

OpenStudy (misty1212):

here is a nice picture of your triangle i don't see any m in it though http://www.wolframalpha.com/input/?i=triangle+%287%2C+5%29%2C+%284%2C+2%29%2C+%289%2C+2%29

OpenStudy (anonymous):

yeah, that doesn't help me.. I don't even understand what the question is tell me nor Geometry it self?

OpenStudy (misty1212):

look carefully at your question you are given the vertices of a triangle, with points labelled A, B, C but then you ask for an angle m there is no m in sight, only A, B, C

OpenStudy (anonymous):

but thats all it gives me?? hmm?

OpenStudy (misty1212):

m usually stands for the measure of some angle but that would be "find m<A:for example

jimthompson5910 (jim_thompson5910):

\[\Large m\angle ABC\] means "angle ABC" where B is the vertex of the angle something like this |dw:1436923873975:dw|

OpenStudy (anonymous):

Here's the question, maybe this is better?

jimthompson5910 (jim_thompson5910):

First you use the distance formula to find the distance from A to B. That will give you the length of AB. Do the same for BC and AC

jimthompson5910 (jim_thompson5910):

tell me what distances you get

OpenStudy (anonymous):

Alrighty ^-^

OpenStudy (anonymous):

My work ^-^

jimthompson5910 (jim_thompson5910):

I don't agree with your last distance of 13

jimthompson5910 (jim_thompson5910):

you forgot to take the square root of 13

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

Square root of 13 is 3.60

jimthompson5910 (jim_thompson5910):

|dw:1436929152566:dw|

jimthompson5910 (jim_thompson5910):

|dw:1436929181793:dw|

jimthompson5910 (jim_thompson5910):

a = 5 b = 3.60555 c = 4.24264 use these three values in the law of cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B) to solve for the value of B

OpenStudy (anonymous):

-173.8115277? Thats what I got?

jimthompson5910 (jim_thompson5910):

b^2 = a^2 + c^2 - 2*a*c*cos(B) 3.60555^2 = 5^2 + 4.24264^2 - 2*5*4.24264*cos(B) are you able to isolate cos(B) ? If not, try replacing "cos(B)" with "x" ie, solve for x in 3.60555^2 = 5^2 + 4.24264^2 - 2*5*4.24264*x

OpenStudy (anonymous):

For 5^2+4.24264^2-2*5*4.24264*x=42.99999417 then 3.60555^2 =12.9999908 and then I'm stuck, If I'm getting any of this right??

jimthompson5910 (jim_thompson5910):

`5^2+4.24264^2-2*5*4.24264*x` will turn into `42.9999941696 - 42.4264*x`

jimthompson5910 (jim_thompson5910):

42.9999941696 - 42.4264*x = 12.9999908025 -42.4264*x = 12.9999908025 - 42.9999941696 -42.4264*x = -30.0000033671 x = -30.0000033671/(-42.4264) x = ???

OpenStudy (anonymous):

Dont understand

jimthompson5910 (jim_thompson5910):

where are you stuck at?

OpenStudy (anonymous):

all of this.. I get .7071069751?

jimthompson5910 (jim_thompson5910):

yes x = 0.7071069751

OpenStudy (anonymous):

oh so I was doing all that right?

jimthompson5910 (jim_thompson5910):

you agree that 5^2 = 25 3.60555^2 = 12.9999908025 4.24264^2 = 17.9999941696 2*5*4.24264 = 42.4264 right?

jimthompson5910 (jim_thompson5910):

yeah if you got to x = 0.7071069751, then you are doing it right

OpenStudy (anonymous):

yeah and awesome

jimthompson5910 (jim_thompson5910):

recall that I replaced "cos(B)" with "x" to make things simpler

jimthompson5910 (jim_thompson5910):

if x = 0.7071069751 then cos(B) = 0.7071069751

OpenStudy (anonymous):

oooh theres more work???

jimthompson5910 (jim_thompson5910):

to find B itself, we apply the arccosine function to both sides cos(B) = 0.7071069751 arccos(cos(B)) = arccos(0.7071069751) B = ???

jimthompson5910 (jim_thompson5910):

just these last steps and you're done

OpenStudy (anonymous):

your killing me man, your killing me haha

jimthompson5910 (jim_thompson5910):

lol what is `arccos(0.7071069751)` equal to ?

jimthompson5910 (jim_thompson5910):

use a calculator like this one if you don't have a calculator with arccos http://web2.0calc.com/

OpenStudy (anonymous):

I got .7602444711?

jimthompson5910 (jim_thompson5910):

http://web2.0calc.com/#arccos(0.7071069751)

jimthompson5910 (jim_thompson5910):

once you click the link, hit enter to have it evaluate

OpenStudy (anonymous):

round it up its 45. Cool

jimthompson5910 (jim_thompson5910):

yeah 44.999984287488 ---> 45

OpenStudy (anonymous):

awesome, Its correct. Thank you, alot

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

Means a lot ^-^

jimthompson5910 (jim_thompson5910):

I'm glad to be of help

OpenStudy (anonymous):

Yay! lol

OpenStudy (ali2x2):

Close the question, But not before you give me a medal :3

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