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Mathematics 18 Online
OpenStudy (anonymous):

I can't believe sometimes that English is my first language. What does this question mean? "Here is a plot of f[x] = x^3 on [-2,2] How does the plot give away the value of Integrate[x^3, {x, -2, 2}] ?​" pictures coming ...

OpenStudy (anonymous):

image attached

OpenStudy (usukidoll):

ok... so we are given a function \[\LARGE f(x) = x^3\] graphed between the intervals of -2 to 2

OpenStudy (anonymous):

OpenStudy (usukidoll):

and then we are asked how the plot of that graph gave away the value when we are integrating from -2 to 2

OpenStudy (usukidoll):

you wouldn't mind if we integrate first right? do you know anti-derivatives?

ganeshie8 (ganeshie8):

Hint : if \(f(x)\) is an odd function, \[\int\limits_{-a}^a f(x)\,dx = 0\]

OpenStudy (anonymous):

I dont mind, but negative on the anti derivatives (I think)

OpenStudy (usukidoll):

when we are taking the antiderivative, we add one to the exponent and divide by the new exponent.

OpenStudy (usukidoll):

so since your exponent is 3. What's 3 +1 ?

OpenStudy (anonymous):

so do they mean, I am to look at the plot, and then work out the value of the integration equation?

OpenStudy (anonymous):

hmmm.. 5-1?

OpenStudy (anonymous):

j/k 4

OpenStudy (usukidoll):

|dw:1436955882543:dw| now evaluate f(b)-f(a) or f(2)-f(-2)

OpenStudy (anonymous):

when the question says.. the value of ... do they mean that the equation itself is a value, or that the equation comes out to some value?

ganeshie8 (ganeshie8):

Notice that the graph is symmetric about origin, so f(x) is an odd function. You don't need to do any further work, the definite integral between a symmetric interval would be simply 0 because the positive area and negative area kill each other out.

OpenStudy (anonymous):

oh, so by looking at the image.. I should see that it is symmetrical about zero, and therefore the sum of it's parts will be a negative area + an equal positive area = zero.

OpenStudy (usukidoll):

yes it is an odd function, so we do have symmetry around the origin . When we graph x^3 only we should have just |dw:1436956009479:dw|

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