Question

Help!

Answer 1

WOULDN'T YOU JUST PLUG THEM IN? \[3(3)^{2}-4(3)+1\]

Answer 2

No because thats not an option

Answer 3

you have to compute the first derivative of the function v(t) at t=3, namely:
\[\Large a\left( t \right) = \frac{d}{{dt}}\left( {3{t^2} - 4t + 1} \right) = ...?\]

Answer 4

6t-4

Answer 5

ok! now replace t with 3, what do you get?

Answer 6

14

Answer 7

correct! your answer is
a=14 feet/sec^2

Answer 8

Thank you so much!

Answer 9

michele is right cause accelration is the rate of change of velocity per time!

Answer 10

thanks!! :)

Answer 11

thanks!! @Hassan3130

Answer 12

Thank you @Hassan3130 !