Question

The expression (secx + tanx)2 is the same as _____.

Answer 1

\[(\sec x + \tan x)^2\]
Remember how to expand out a squared expression like this? :)

Answer 2

\[(\frac{ 1 }{ cosx }+\frac{ sinx }{ cosx})^2 ?\]

Answer 3

Before we continue, is there by chance choices?

Answer 4

yes hold on...

Answer 5

If you're able to get past that first part,
here is a hint to help you finish it up.
Remember your Pythagorean identity for tangent,
\[\sec ^2x=1+\tan ^2x\]

Answer 6

\[A. 1+2\tan^2+2secx tanx\]
\[B. 1+2cscx\]
\[C. \sec^2x+\tan^2x\]
\[D. \sec^2x+2cscx+\tan^2x\]

Answer 7

These are the choices

Answer 8

Well after you expand you would get

\[\sec^2(x)+2\sec(x)\tan(x)+\tan^2(x)\]

Answer 9

But remember after you expand everything out, you can replace the sec^2x(that you'll end up with) with 1+tan^2x.

Answer 10

I'm so lost
What I have so far is 1+tan(x)+2sec(x)tan(x)+1

Answer 11

Expand the original equation like you would a binomial

Answer 12

except in this case instead of (a+b)^2

A is Sec (x) and B is Tan (x)

Answer 13

look at my previous posts, they are the exact steps on how to do this.

Answer 14

so it's A

Answer 15

yes

Answer 16

thank you