I'll fan and medal ;
Which recursive formula can be used to generate the sequence shown, where f(1) = 9.6 and n 1?

9.6, –4.8, 2.4, –1.2, 0.6, ...

f(n + 1) = –0.5f(n)
f(n + 1) = 0.5f(n)
f(n + 1) = f(0.5n)
f(n + 1) = f(–0.5n)

Question

I'll fan and medal ;>
Which recursive formula can be used to generate the sequence shown, where f(1) = 9.6 and n > 1?

9.6, –4.8, 2.4, –1.2, 0.6, ...

f(n + 1) = –0.5f(n)
f(n + 1) = 0.5f(n)
f(n + 1) = f(0.5n)
f(n + 1) = f(–0.5n)

anonymous · Answer

think of $f(n)$ as 'some term', and $f(n+1)$ as 'the term afterward' -- this should make it potentially easier to understand

anonymous · Answer

A

jdoe0001 · Answer

hmmm test the sequence pattern, see if it gives you those numbers

jdoe0001 · Answer

keep in mind that f(n+1)   simply means
"the following number"

so if you're in the 3rd term,  n = 3, and want the 4th term, or n+1
then that'd be n = 3, thus n+1 is  3+1 or f(4)
and so on

anonymous · Answer

So how would I solve it?

jdoe0001 · Answer

well, you could try testing the given choices
see which one gives you the correct next value