Question

Where is (x+2)/((x^2-2x-8) discontinuous

Answer 1

Oh. Where a line is discontinuous is basically where a point on the graph of the function cannot exist. This is indicated by a open circle on the graph.

Answer 2

So to first do this, factor the denominator of \[(x+2)/((x^2-2x-8) \]

Answer 3

(x+2)(x-4)

Answer 4

Yes! Just another side note, is there by chance answer choices?

Answer 5

–2
–2, 4
4
f(x) is continuous everywhere

Answer 6

So the function cannot exist if the denominator equals 0. So this means...?

Answer 7

It has a discontinuity?

Answer 8

Basically you have to find the "zeroes" of the denominator,

So x - 4 = 0, and x+2 = 0

Answer 9

SO if you solve for x, what would they be?

Answer 10

Hello?

Answer 11

Sorry internet trouble

Answer 12

So it would be 4 and -2

Answer 13

@whatdoesthismean

Answer 14

yes. thats correct. sorry i was helping another person