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Mathematics 15 Online
OpenStudy (anonymous):

I'm confused on something can anyone help? for medal?

OpenStudy (anonymous):

Which function below is the inverse of f(x) = The quantity of three x plus five, over seven.?

OpenStudy (anonymous):

f−1(x) = The quantity of seven x minus five, over three f−1(x) = The quantity of seven x plus five, over three −f−1(x) = Seven over the quantity of three x plus five f−1(x) = Seven over the quantity of five minus three x

Mehek (mehek14):

\(\dfrac{3x+5}{7}\) ?

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

@DJthereal here's something i need help on

OpenStudy (anonymous):

@LynFran

OpenStudy (anonymous):

option First. want solution?

OpenStudy (anonymous):

LOL, i'm lost? what do you mean whats the solution A. f−1(x) = The quantity of seven x minus five, over three B. f−1(x) = The quantity of seven x plus five, over three C. −f−1(x) = Seven over the quantity of three x plus five D .f−1(x) = Seven over the quantity of five minus three x

OpenStudy (anonymous):

A is correct! solution means how to get it!

OpenStudy (anonymous):

whats tha equation??

OpenStudy (anonymous):

nvm i see

OpenStudy (anonymous):

A sounds good. but y A?

OpenStudy (anonymous):

i think its B or A

OpenStudy (anonymous):

@DJthereal same but i think someone needs to show me how to find the answer. i have a test coming up soon. thats why i'd ask why it's A.

OpenStudy (anonymous):

1 sec...i had a problem similar to this but i can't find my old notebook

OpenStudy (anonymous):

\[f(x)=\frac{ 7x-5 }{ 3}\\ switch \ x\ and\ f(x)\\ x=\frac{ 7f(x)-5 }{ 3 }\\solving \ for\ f(x)\\f(x)=\frac{ 3x+5 }{ 7}\\putting\ f(x)= inverse\ f(x)\\ \therefore \ inverse\ f(x)= \frac{ 3x+5 }{ 7 }\]

OpenStudy (anonymous):

thats A??

OpenStudy (anonymous):

wait which one did @eninone jus solve??

OpenStudy (anonymous):

what are tha answer choices??

OpenStudy (anonymous):

oh! no ! a plus sign missed! hey! @nerlineg check out my solution, Option A is Correct.

OpenStudy (anonymous):

\[given\ f(x) = \frac{ 3x+5 }{ 7}\\ switch\ x\ and \ f(x)\\ i.e. x \ becomes\ f(x) \ and \ f(x) \ becomes\ x\\ x=\frac{ 3f(x)+5 }{ 7},\ solve\ for\ f(x)\\7x=3f(x)+5\\7x-5=3f(x)\\f(x)=\frac{ 7x-5 }{ 3 }\\replace\ f(x) \ by\ inverse\ f(x)\\i.e.,\ inverse\ f(x)=\frac{ 7x-5 }{ 3 }\\clearly\ option\ A \ is\ Correct!\]

OpenStudy (ybarrap):

Yes, @eninone has the correct solution.

OpenStudy (anonymous):

yeah, my teacher did a typo, but yup you are right thanks ! i actually do understand it now. with everyone's help on here ! @eninone @ DJthereal

OpenStudy (anonymous):

@DJthereal

OpenStudy (anonymous):

You should read 'How to Sove it' by George Polya. https://en.wikipedia.org/wiki/George_P%C3%B3lya http://www-history.mcs.st-andrews.ac.uk/Biographies/Polya.html

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