Question

Consider the functions f(x) = 2x + 1 and g(x) = x2 − 10. What is the value of f[g(3)]?

39
−3
−7
-1

Answer 1

you start from the inside then work your way through outside

Answer 2

first, solve
g(x) since you are being asked to solve g(3) in the innermost function.

Answer 3

x^3-10?

Answer 4

-10?

Answer 5

@pooja195

Answer 6

g(3) here x =3
so replace x by 3 not the exponent...

Answer 7

so (3)-10?

Answer 8

and where is exponent 2 ??

Answer 9

(3)^2-10?

Answer 10

\[\huge\rm g(\color{reD}{x}) = \color{red}{x}^2 -10\]

Answer 11

yes right!

Answer 12

and then substitute g(3) into f(x) function

Answer 13

yikes, idk how

Answer 14

so what is g(3) =??

Answer 15

\(\color{blue}{\text{Originally Posted by}}\) @lealealea222
(3)^2-10?
\(\color{blue}{\text{End of Quote}}\)
=what ?

Answer 16

-1

Answer 17

so what is g(3) ?

Answer 18

i think -1

Answer 19

okay now use f(x) being that x is -1

Answer 20

is the answer -3 ?

Answer 21

look at this and tell me what you observe
given: f(x) = 2x + 1 and g(x) = x2 − 10

\(f(x) = 2(x^2-10) +1 \)

Answer 22

tick tock tick tock lol

Answer 23

man...

Answer 24

idk haha

Answer 25

did you notice that I put the g(x) function into the f(x) function

Answer 26

yes

Answer 27

look at it again

Answer 28

you put them together

Answer 29

i think its -3

Answer 30

how so what is \(2 \times (-1) \)

Answer 31

-2x

Answer 32

it's not variable x, but the multiplication operation

Answer 33

use the number line I drew and place where -2 is

Answer 34

oh ok let me do that again

Answer 35

-2

Answer 36

use the number line I drew and place where -2 is

Answer 37

click the pencil icon on the upper right hand corner of my drawing so you can use it

Answer 38

?