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Mathematics 15 Online
OpenStudy (anonymous):

Find the indicated limit, if it exists. http://prntscr.com/7ulwx5

OpenStudy (solomonzelman):

for the part of the function that is GREATER than 9, that is: \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{+}}f(x)\) --------------------------------------------------- for the part of the function that is SMALLER than 9, that is: \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{-}}f(x)\)

OpenStudy (solomonzelman):

If these both limits are equal to each other, then whatever they are both equivalent to, is going to be your answer. If the limit from the left side and the limit from the right side are not equivalent, then your limit DNE

OpenStudy (solomonzelman):

If you don't understand what I am saying I can redo the explanation better.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I understand what you are saying. I just need to know how to find the limit.

OpenStudy (solomonzelman):

Just plug in 9 into each of the parts

OpenStudy (anonymous):

ok so 18 and 18

OpenStudy (solomonzelman):

yes, so your answer is 18

OpenStudy (anonymous):

thanks

OpenStudy (solomonzelman):

because the limit from both sides is equal to 18, that means that the two-sided limit is also 18.

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

\(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{-}}f(x)=\lim_{x\rightarrow 9}(x+9)=9+9=18\) \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{+}}f(x)=\lim_{x\rightarrow 9}(27-x)=27-9=18\) Therefore, \(\displaystyle \LARGE\lim_{x\rightarrow 9}f(x)=18\)

OpenStudy (solomonzelman):

the 27-x corresponds to the limit from the right side, because it is for greater-than-9 values of x, and x+9 corresponds to the limit from the left side, because it is for smaller-than-9 values of x.

OpenStudy (solomonzelman):

You are welcome...

OpenStudy (anonymous):

That helps a lot. Thank you

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