Question

hey i have 2 quick questions if anyone can help

Answer 1

A student is trying to solve the system of two equations given below:

Equation P: y + z = 6
Equation Q: 3y + 4z = 1

Which of the following is a possible step used in eliminating the y-term?

Answer 2

is this type a typed answer?

Answer 3

(y + z = 6) ⋅ 4
(3y + 4z = 1) ⋅ 4
(y + z = 6) ⋅ −3
(3y + 4z = 1) ⋅ 3

Answer 4

To eliminate a variable, you need to add the equations or multiples of the equations in which the same variable in both equations will add to zero.

Answer 5

In order to elminiate any term from an equation when you have multiple equations .. U've to multiply one with the first equation that will result in a "zero" when you add them up ...

In Ur case, this would be the third choice :D

Let me know if U got it :)

Answer 6

Ok

Answer 7

oh i get it that makes sence

Answer 8

You want to eliminate y.
The second equation has 3y.
If you could change the first equation to have -3y, that would do it.
Does any choice change the first equation so that the y term becomes -3y?

Answer 9

sorry I meant to multiply by a constant factor :)

Answer 10

ya thats what i try but i kept getting stuck

Answer 11

can u guys help me out with one more

Answer 12

Feel free :D

Answer 13

ok

Answer 14

A set of equations is given below:

Equation E: c = 2d + 1
Equation F: c = 3d + 7

Which statement describes a step that can be used to find the solution to the set of equations?
Equation F can be written as c = 3(c − 1) + 7.
Equation F can be written as c = 2(c − 7) + 1.
Equation F can be written as d + 1 = 3d + 7.
Equation F can be written as 2d + 1 = 3d + 7.

Answer 15

Just find d in term of c from Equation E and then plug the value in the other equation or find c in terms of d and do same steps :)

Answer 16

Let's try to get c in terms of d .. To do so, U've to get c in one hand and d on the other hand in one of the equations let's say equation E .. we already have that done for us .. then plug c in equation F and see if any of the answers is what we have got

Answer 17

Second problem.
Look at the given equations. Notice they are both solved for c.
Set them equal to each other.
If c = 2d + 1 and
c = 3d + 7, then
2d + 1 must equal 3d + 7
Which choice shows this?

Answer 18

If none of them is what we got .. Then we are now sure that the answer contains no d's !
So we try the other way .. Try to get d in terms of c from Equation E and plug it in equation F as well as what we have did in the last step for c in terms of d