Question

URGENT HElP
Where did I go wrong in my problem?!?!?

Answer 1

so we have the quadratic equation
\[x^2+6x+3\]
using the discriminant formula \[ b^2-4ac \]
we have
\[(6)^2-4(1)(3) =36-12 =24\]
which is not a perfect square.
I need to grab the latex for the quadratic equation brb

Answer 2

ok, I'll be here

Answer 3

\[{x = \frac{{ - 6 \pm \sqrt {24} }}{{2}}} \]

Answer 4

ok the problem lies in the square root... yes it is 24, but we can simplify that further.

Answer 5

so we need to find the smallest perfect square number

Answer 6

Oh I get it, so we can do √6 √4 which simplifies into 2√6 which would go away when divided by 2. right?

Answer 7

yeah

Answer 8

Also how do I explain why I chose this method?

Answer 9

\[{x = \frac{{ - 6 \pm \sqrt {4 \cdot 6 } }}{{2}}} \rightarrow {x = \frac{{ - 6 \pm 2\sqrt {6} }}{{2}}}\]

\[x = \frac{-6}{2} \pm \frac{2\sqrt{6}}{2} \rightarrow -3 \pm \sqrt{6}\]

Answer 10

First of all, we can't factor this equation. Using the discriminant formula, we obtain 24 and that's not a perfect square number. Therefore, we have to use the quadratic formula.

Answer 11

Completing the square is useless because we are given a quadratic equation which is similar to the standard quadratic formula of \[ax^2+bx+c \]

Answer 12

I don't think we can do graphing either... our equation doesn't start with y =... that's kind of a generic excuse though.

Answer 13

Ok thank you SO much