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Mathematics 10 Online
OpenStudy (anonymous):

Find the domain of the function f of x equals the square root of the quantity x minus 2, plus three A. x > or equal to 2 B. x < -2 C. x > 2 D. x > or equal to 2

OpenStudy (anonymous):

@welshfella @mathstudent55

OpenStudy (welshfella):

f(x) = sqrt(x - 2) + 3

OpenStudy (welshfella):

the domain is the possible values of x - now we have another square root here and x - 2 cannot be negative - so what values of x - 2 make it greater than or equal to zero?

OpenStudy (anonymous):

3?

OpenStudy (welshfella):

we are looking for a range ov values not one value what we are doing really is solving the inequality x - 2 >= 0

OpenStudy (anonymous):

so its A?

OpenStudy (welshfella):

yes x >= 2 A

OpenStudy (welshfella):

D is the same thing - maybe theres a typ there

OpenStudy (anonymous):

yeah it was supposed to be -2 for D haha

OpenStudy (welshfella):

ok well i gotta go hope you understand better now

OpenStudy (anonymous):

thanks for the help means a lot

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