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Find the domain of the function f of x equals the square root of the quantity x minus 2, plus three A. x > or equal to 2 B. x < -2 C. x > 2 D. x > or equal to 2
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@welshfella @mathstudent55
f(x) = sqrt(x - 2) + 3
the domain is the possible values of x - now we have another square root here and x - 2 cannot be negative - so what values of x - 2 make it greater than or equal to zero?
3?
we are looking for a range ov values not one value what we are doing really is solving the inequality x - 2 >= 0
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so its A?
yes x >= 2 A
D is the same thing - maybe theres a typ there
yeah it was supposed to be -2 for D haha
ok well i gotta go hope you understand better now
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thanks for the help means a lot
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